785=4t^2+56

Solution for 785=4t^2+56 equation:

785=4t^2+56

We move all terms to the left:

785-(4t^2+56)=0

We get rid of parentheses

-4t^2-56+785=0

We add all the numbers together, and all the variables

-4t^2+729=0

a = -4; b = 0; c = +729;
Δ = b2-4ac
Δ = 02-4·(-4)·729
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*-4}=\frac{-108}{-8}
=13+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*-4}=\frac{108}{-8}
=-13+1/2
$